From the question it is given that,
$3-2x\ge x-12$
So, by transposing we get,
$2x+x\le 12+3$
$3x\le 15$
$3x\le 15$
$x\le 15/3$
$x\le 5$
As per the condition given in the question, x ∈ W.
Therefore, solution set $x=\{1,2,3,4,5\}$
From the question it is given that,
$3-2x\ge x-12$
So, by transposing we get,
$2x+x\le 12+3$
$3x\le 15$
$3x\le 15$
$x\le 15/3$
$x\le 5$
As per the condition given in the question, x ∈ W.
Therefore, solution set $x=\{1,2,3,4,5\}$