$x-2>0$ and $3 x<18$

$x-2>0$

$x-2+2>0+2$

$x>2$

$\therefore \mathrm{X} \in(2, \infty) \ldots(1)$

Now,

$3 x<18$

Dividing both the sides by 3 we get,

$3 x / 3<18 / 3$

$\mathrm{x}<6$

$\therefore \mathrm{x} \in(-\infty, 6) \ldots(2)$

From (1) and (2), we get

$\mathrm{X} \in(2, \infty) \cap(-\infty, 6)$

$\mathrm{x} \in(2,6)$

$\therefore$ The solution of the given system of inequations is $(2,6)$.