solution:

Case I:

T1, T2 are triangle.

R = {(T1, T2): T1 is like T2}

Check for reflexive:

As We realize that every triangle is like itself, so (T1, T1) ∈ R is reflexive.

Check for symmetric:

Likewise two triangles are comparable, then, at that point T1 is like T2 and T2 is like T1, so (T1, T2) ∈ R and (T2, T1) ∈ R

R is symmetric.

Check for transitive:

Once more, on the off chance that, T1 is like T2 and T2 is like T3, then, at that point T1 is like T3 , so (T1, T2) ∈ R and (T2, T3) ∈ R and (T1, T3) ∈ R

R is transitive

Consequently, R is an identical connection.

Case 2: It is given that T1, T2 and T3 are correct calculated triangles.

T1 with sides 3, 4, 5

T2 with sides 5, 12, 13 and

T3 with sides 6, 8, 10

Since, two triangles are comparable if relating sides are corresponding. Consequently, 3/6 = 4/8 = 5/10 = 1/2

Consequently, T1 and T3 are connected.