SOLUTION:
\[\begin{array}{*{35}{l}}
x\text{ }+\text{ }2y\text{ }\le \text{ }3 \\
{} \\
\end{array}\]
\[Line:\text{ }x\text{ }+\text{ }2y\text{ }=\text{ }3\]
x | 3 | 1 |
y | 0 | 1 |
Also, (0, 0) satisfies the\[x\text{ }+\text{ }2y\text{ }\le \text{ }3\] , hence region is towards the origin
\[Line:\text{ }3x\text{ }+\text{ }4y\text{ }=\text{ }12\]
x | 0 | 4 |
y | 3 | 0 |
Also, (0, 0) satisfies the\[3x\text{ }+\text{ }4y\text{ }\le \text{ }3\] , hence region is towards the origin
x ≥ 0 ⇒ region is to the right of the y-axis
And, y ≥ 1 ⇒ region is up above the line x = 1,
Hence, we can conclude from the graph that the above system has no common region as solution
.