Answer:
Consider,
q: x is an integer and x2 is odd.
r: x is an odd integer.
p: if q, then r.
Let r be false.
x is not an odd integer, then x is an even integer
x = (2n) for some integer n
x2 = 4n2
x2 is an even integer
q is False
r is false and q is false
Thus, p: “ if q, then r” is a true statement.