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Show that the complex number z, satisfying the condition arg ((z-1)/(z+1)) = π/4 lies on a circle.

Let \[z\text{ }=\text{ }x\text{ }+\text{ }iy\]

arg \[\left( \left( z-1 \right)/\left( z+1 \right) \right)\text{ }=\text{ }\pi /4\]

\[\Rightarrow ~arg\text{ }\left( z\text{ }\text{ }1 \right)\text{ }\text{ }-arg\text{ }\left( z\text{ }+\text{ }1 \right)\text{ }=\text{ }\pi /4\]

\[\Rightarrow ~arg\text{ }\left( x\text{ }+\text{ }iy\text{ }\text{ }1 \right)\text{ }\text{ }-arg\text{ }\left( x\text{ }+\text{ }iy\text{ }+\text{ }1 \right)\text{ }=\text{ }\pi /4\]

\[\Rightarrow ~arg\text{ }\left( x+\text{ }\text{ }1\text{ }+\text{ }iy \right)\text{ }\text{ }-arg\text{ }\left( x\text{ }+\text{ }1\text{ }+\text{ }iy \right)\text{ }=\text{ }\pi /4\]

NCERT Exemplar Solutions For Class 11 Maths Chapter 5-14

\[\Rightarrow ~{{x}^{2}}~+\text{ }{{y}^{2}}~\text{ }-1\text{ }=\text{ }2y\]

\[\Rightarrow ~{{x}^{2}}~+\text{ }{{y}^{2}}~\text{ }-2y\text{ }\text{ }-1\text{ }=\text{ }0\]

The equation obtained represents the equation of a circle.