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Show that \[\mathbf{cos}\text{ }\left( \mathbf{2}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}~\mathbf{1}/\mathbf{7} \right)\text{ }=\text{ }\mathbf{sin}\text{ }(\mathbf{4}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}~\mathbf{1}/\mathbf{3}).\]
Show that \[\mathbf{cos}\text{ }\left( \mathbf{2}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}~\mathbf{1}/\mathbf{7} \right)\text{ }=\text{ }\mathbf{sin}\text{ }(\mathbf{4}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}~\mathbf{1}/\mathbf{3}).\]
CBSE | Class 12 | Exercise 1 | Inverse Trigonometric Functions | Maths | NCERT Exemplar
Show that \[\mathbf{cos}\text{ }\left( \mathbf{2}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}~\mathbf{1}/\mathbf{7} \right)\text{ }=\text{ }\mathbf{sin}\text{ }(\mathbf{4}\text{ }\mathbf{ta}{{\mathbf{n}}^{-\mathbf{1}}}~\mathbf{1}/\mathbf{3}).\]

Taking L.H.S, we have

Thus, L.H.S = R.H.S

– Hence proved

i

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