Solution:

(i) In the form of conditional statement, expression is

If $p$, then $q$

So now,

In the statement $p$ and $q$ are

$p$: Any number is prime,

$q$: square of number is not prime.

As a result, if any number is prime, then its square is not prime.

Solution:

(ii) In the form of conditional statement, expression is

If $p$, then $q$

So now,

In the statement $p$ and $q$ are

$p$: a, b and c are in AP

$q$: $2b=a + c$

As a result, if a, b, c are in AP then $2b=a + c$.