Represent the following situations in the form of quadratic equations: (i) The area of a rectangular plot is 528 m2. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot. (ii) The product of two consecutive positive integers is 306. We need to find the integers.
Represent the following situations in the form of quadratic equations: (i) The area of a rectangular plot is 528 m2. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot. (ii) The product of two consecutive positive integers is 306. We need to find the integers.

Solutions:

(i) Let us consider,

Breadth of the rectangular plot = x m

Thus, the length of the plot = (2x + 1) m.

As we know,

$Area\text{ }of\text{ }rectangle\text{ }=\text{ }length~\times ~breadth\text{ }=\text{ }528\text{ }{{m}^{2}}$

Putting the value of length and breadth of the plot in the formula, we get,

$\left( 2x~+\text{ }1 \right)\text{ }\times ~x~=\text{ }528$

$\Rightarrow 2{{x}^{2}}~+~x~=528$

$\Rightarrow 2{{x}^{2}}~+~x-528\text{ }=\text{ }0$

Therefore, the length and breadth of plot, satisfies the quadratic equation, $2{{x}^{2}}~+~x-528\text{ }=\text{ }0$, which is the required representation of the problem mathematically.

(ii) Let us consider,

The first integer number = x

Thus, the next consecutive positive integer will be = x + 1

Product of two consecutive integers $=~x~\times ~\left( x~+1 \right)\text{ }=\text{ }306$

$\Rightarrow ~{{x}^{2~}}+~x~=\text{ }306$

$\Rightarrow ~{{x}^{2~}}+~x-306\text{ }=\text{ }0$

Therefore, the two integers x and x+1, satisfies the quadratic equation, ${{x}^{2~}}+~x-306\text{ }=\text{ }0$ , which is the required representation of the problem mathematically.