Reduce the following equations into intercept form and find their intercepts on the axes. (iii) 3y + 2 = 0
Reduce the following equations into intercept form and find their intercepts on the axes. (iii) 3y + 2 = 0

\[\left( \mathbf{iii} \right)\text{ }\mathbf{3y}\text{ }+\text{ }\mathbf{2}\text{ }=\text{ }\mathbf{0}\]

Given:

 

The condition is \[\mathbf{3y}\text{ }+\text{ }\mathbf{2}\text{ }=\text{ }\mathbf{0}\]

Condition of line in capture structure is given by\[\mathbf{x}/\mathbf{a}\text{ }+\text{ }\mathbf{y}/\mathbf{b}\text{ }=\text{ }\mathbf{1}\] , where ‘a’ and ‘b’ are blocks on x pivot and y – hub separately.

 

In this way, \[\mathbf{3y}\text{ }=\text{ }-\text{ }\mathbf{2}\]

 

Presently, let us partition the two sides by – 2, we get

 

\[\mathbf{3y}/\text{ }-\text{ }\mathbf{2}\text{ }=\text{ }-\text{ }\mathbf{2}/\text{ }-\text{ }\mathbf{2}\]

\[\mathbf{3y}/\text{ }-\text{ }\mathbf{2}\text{ }=\text{ }\mathbf{1}\]

\[\mathbf{y}/\left( -\text{ }\mathbf{2}/\mathbf{3} \right)\text{ }=\text{ }\mathbf{1}\]

The above condition is of the structure\[\mathbf{x}/\mathbf{a}\text{ }+\text{ }\mathbf{y}/\mathbf{b}\text{ }=\text{ }\mathbf{1}\] , where \[\mathbf{a}\text{ }=\text{ }\mathbf{0},\text{ }\mathbf{b}\text{ }=\text{ }-\text{ }\mathbf{2}/\mathbf{3}\]

Capture on x – axis is\[~\mathbf{0}\]  

 

Capture on y – axis is \[-\text{ }\mathbf{2}/\mathbf{3}\]