\[\left( \mathbf{iii} \right)\text{ }\mathbf{3y}\text{ }+\text{ }\mathbf{2}\text{ }=\text{ }\mathbf{0}\]
Given:
The condition is \[\mathbf{3y}\text{ }+\text{ }\mathbf{2}\text{ }=\text{ }\mathbf{0}\]
Condition of line in capture structure is given by\[\mathbf{x}/\mathbf{a}\text{ }+\text{ }\mathbf{y}/\mathbf{b}\text{ }=\text{ }\mathbf{1}\] , where ‘a’ and ‘b’ are blocks on x pivot and y – hub separately.
In this way, \[\mathbf{3y}\text{ }=\text{ }-\text{ }\mathbf{2}\]
Presently, let us partition the two sides by – 2, we get
\[\mathbf{3y}/\text{ }-\text{ }\mathbf{2}\text{ }=\text{ }-\text{ }\mathbf{2}/\text{ }-\text{ }\mathbf{2}\]
\[\mathbf{3y}/\text{ }-\text{ }\mathbf{2}\text{ }=\text{ }\mathbf{1}\]
\[\mathbf{y}/\left( -\text{ }\mathbf{2}/\mathbf{3} \right)\text{ }=\text{ }\mathbf{1}\]
∴ The above condition is of the structure\[\mathbf{x}/\mathbf{a}\text{ }+\text{ }\mathbf{y}/\mathbf{b}\text{ }=\text{ }\mathbf{1}\] , where \[\mathbf{a}\text{ }=\text{ }\mathbf{0},\text{ }\mathbf{b}\text{ }=\text{ }-\text{ }\mathbf{2}/\mathbf{3}\]
Capture on x – axis is\[~\mathbf{0}\]
Capture on y – axis is \[-\text{ }\mathbf{2}/\mathbf{3}\]