Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 \(\ohm\)resistor. What would be the readings in the ammeter and the voltmeter?
Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12 \(\ohm\)resistor. What would be the readings in the ammeter and the voltmeter?

To measure the potential difference, an ammeter should always be linked in series with resistors, while a voltmeter should be connected in parallel with the resistor, as illustrated in the diagram below.

The ammeter and voltmeter readings may be obtained using Ohm’s Law.

The circuit has a total resistance of 5 + 8 + 12 = 25.

Because we know that the circuit’s potential difference is 6 V, we can calculate the current flowing through the circuit or via the resistors as follows:

6/25 = 0.24A = I = V/R

Allow V1 to represent the potential difference across the 12 resistor.

V1 may be computed using the current obtained as follows:

V1 = 0.24A

As a result, the ammeter will show 0.24 A and the voltmeter will read 2.88 V.