(xi)
From the question firstly we consider Left Hand Side (LHS),
$={{\sin }^{4}}B+{{\cos }^{4}}B$
$=1-2{{\sin }^{2}}B{{\cos }^{2}}B$
$={{\sin }^{4}}B+{{\cos }^{4}}B+2{{\sin }^{2}}B{{\cos }^{2}}B$
$=\left( {{\sin }^{2}}B \right)+{{\left( {{\cos }^{2}}B \right)}^{2}}+2{{\sin }^{2}}B{{\cos }^{2}}B-2{{\sin }^{2}}B{{\cos }^{2}}B$
[Adding and subtracting $2{{\sin }^{2}}A{{\cos }^{2}}A$]
$={{\left( {{\sin }^{2}}B+{{\cos }^{2}}B \right)}^{2}}-2{{\sin }^{2}}B{{\cos }^{2}}B$
$=1-2{{\sin }^{2}}B{{\cos }^{2}}B$
Then, Right Hand Side (RHS) $=1-2{{\sin }^{2}}B{{\cos }^{2}}B$
Therefore, LHS = RHS