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Prove that the following sets of three lines are concurrent: (i) 15x – 18y + 1 = 0, 12x + 10y – 3 = 0 and 6x + 66y – 11 = 0 (ii) 3x – 5y – 11 = 0, 5x + 3y – 7 = 0 and x + 2y = 0

\[\left( \mathbf{i} \right)~15x\text{ }\text{ }18y\text{ }+\text{ }1\text{ }=\text{ }0,\text{ }12x\text{ }+\text{ }10y\text{ }\text{ }3\text{ }=\text{ }0\]

and

\[6x\text{ }+\text{ }66y\text{ }\text{ }11\text{ }=\text{ }0\]

Given:

\[15x\text{ }\text{ }18y\text{ }+\text{ }1\text{ }=\text{ }0\text{ }\ldots \ldots \text{ }\left( i \right)\]

\[12x\text{ }+\text{ }10y\text{ }\text{ }3\text{ }=\text{ }0\text{ }\ldots \ldots \text{ }\left( ii \right)\]

and

\[6x\text{ }+\text{ }66y\text{ }\text{ }11\text{ }=\text{ }0\text{ }\ldots \ldots \text{ }\left( iii \right)\]

Now, consider the following determinant:

\[=>\text{ }1320\text{ }\text{ }2052\text{ }+\text{ }732\text{ }=\text{ }0\]

Hence proved, the given lines are concurrent.

\[\left( \mathbf{ii} \right)~3x\text{ }\text{ }5y\text{ }\text{ }11\text{ }=\text{ }0,\text{ }5x\text{ }+\text{ }3y\text{ }\text{ }7\text{ }=\text{ }0\text{ }and\text{ }x\text{ }+\text{ }2y\text{ }=\text{ }0\]

Given:

\[3x~-~5y~-~11\text{ }=\text{ }0~\ldots \ldots ~\left( i \right)\]

\[5x\text{ }+\text{ }3y~-~7\text{ }=\text{ }0~\ldots \ldots ~\left( ii \right)\]

And ,

\[x\text{ }+\text{ }2y\text{ }=\text{ }0~\ldots \ldots ~\left( iii \right)\]

Now,

Hence, the given lines are concurrent.