Solution:
\[=\text{ }sin\text{ }{{90}^{o}}\]
\[=\text{ }1\]
\[=\text{ }RHS\]
\[\therefore LHS\text{ }=\text{ }RHS\]
Hence proved.
Solution:
\[=\text{ }sin\text{ }{{90}^{o}}\]
\[=\text{ }1\]
\[=\text{ }RHS\]
\[\therefore LHS\text{ }=\text{ }RHS\]
Hence proved.