(i)
(ii)
Solution:
(i)
\[=\text{ }sin\text{ }{{90}^{o}}\]
\[=\text{ }1\]
\[=\text{ }RHS\]
\[\therefore LHS\text{ }=\text{ }RHS\]
Hence proved.
(ii)
\[=\text{ }sin\text{ }{{60}^{o}}\]
\[=\text{ }\surd 3/2\]
\[=\text{ }RHS\]
\[\therefore LHS\text{ }=\text{ }RHS\]
Hence proved.