Solution:
We know that, there are totally \[9\] cards from which one card is drawn.
Total number of elementary events \[=\text{ }n\left( S \right)\text{ }=\text{ }9\]
\[\left( i \right)\] From numbers \[2\text{ }to\text{ }10\], there are \[5\] even numbers i.e. \[2,\text{ }4,\text{ }6,\text{ }8,\text{ }10\]
So, favorable number of events \[=\text{ }n\left( E \right)\text{ }=\text{ }5\]
Hence, probability of selecting a card with an even number \[=\text{ }n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }5/9\]
\[\left( ii \right)\] From numbers \[2\text{ }to\text{ }10\], there are \[3\] numbers which are multiples of i.e\[.\text{ }3,\text{ }6,\text{ }9\]
So, favorable number of events \[=\text{ }n\left( E \right)\text{ }=\text{ }3\]