Three oxoacids of nitrogen:
1.Nitric acid(HNO3)
2.Nitrous acid (HNO2)
3.Hyponitrous acid (H2N2O1)
+ 3 oxidation is shown by HNO2, Therefore it undergoes disproportion reaction,
Calculation:
Consider,
Oxidation state of N is x.
3HNO2 → HNO3 + 2NO +H2O
The oxidation state of nitrogen in HNO2 is +3
X + (+1) +2*(-2) = 0, x= +3
The oxidation state of nitrogen in HNO3 is +5
X + (+1) + 3*(-2) = 0, x= 5
The oxidation state of nitrogen in NO is +2
X + (-2) = 0, x =2
Hence, +3 oxidation state changes to +5 and +2 oxidation states.