Name three oxoacids of nitrogen. Write the disproportionation reaction of that oxoacid of nitrogen in which nitrogen is in +3 oxidation state.
Name three oxoacids of nitrogen. Write the disproportionation reaction of that oxoacid of nitrogen in which nitrogen is in +3 oxidation state.

Three oxoacids of nitrogen:

1.Nitric acid(HNO3)

2.Nitrous acid (HNO2)

3.Hyponitrous acid (H2N2O1)

+ 3 oxidation is shown by HNO2, Therefore it undergoes disproportion reaction,

Calculation:

Consider,

Oxidation state of N is x.

3HNO2 → HNO3 + 2NO +H2O

The oxidation state of nitrogen in HNO2 is +3

X + (+1) +2*(-2) = 0, x= +3

The oxidation state of nitrogen in HNO3 is +5

X + (+1) + 3*(-2) = 0, x= 5

The oxidation state of nitrogen in NO is +2

X + (-2) = 0, x =2

Hence, +3 oxidation state changes to +5 and +2 oxidation states.