Mark the tick against the correct answer in the following: Range of $\tan ^{-1} x$ is
A. $\left(0, \frac{\pi}{2}\right)$
B. $\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)$
C. $\left[\frac{\pi}{2}, \frac{\pi}{2}\right]$
D. None of these
Mark the tick against the correct answer in the following: Range of $\tan ^{-1} x$ is
A. $\left(0, \frac{\pi}{2}\right)$
B. $\left(\frac{-\pi}{2}, \frac{\pi}{2}\right)$
C. $\left[\frac{\pi}{2}, \frac{\pi}{2}\right]$
D. None of these

Solution:

Option(B) is correct.
To Find: The range of $\tan ^{-1} x$
Here, the inverse function is given by $y=f^{-1}(x)$
The graph of the function $y=\tan ^{-1}(x)$ can be obtained from the graph of $Y=\tan x$ by interchanging $x$ and $y$ axes. $i . e$, if $(a, b)$ is a point on $Y=\tan x$ then $(b$, $a)$ is the point on the function $y=\tan ^{-1}(x)$
Below is the Graph of the range of $\tan ^{-1}(x)$


From the graph, it is clear that the range of $\tan ^{-1}(x)$ is restricted to any of the intervals like $\left[-\frac{3 \pi}{2},-\frac{\pi}{2}\right],[$ $\left.-\frac{\pi}{2}, \frac{\pi}{2}\right],\left[\frac{\pi}{2}, \frac{3 \pi}{2}\right]$ and so on. Hence the range is given by
$\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$