Solution:
Since 1<a< 5,
$a = 2, 3, 4$
Therefore, R $= {\{(2,{\frac12}), (3,{\frac13}), (4,{\frac14})}\}$
As a result, Domain(R) = {2, 3, 4}
and Range(R) = ${\{{\frac12},{\frac13},{\frac14}}\}$
Solution:
Since 1<a< 5,
$a = 2, 3, 4$
Therefore, R $= {\{(2,{\frac12}), (3,{\frac13}), (4,{\frac14})}\}$
As a result, Domain(R) = {2, 3, 4}
and Range(R) = ${\{{\frac12},{\frac13},{\frac14}}\}$