Login/Sign Up
Let f : R – { -4/3 } → R be a function defined as f(x) = ????????/3????+????. The inverse of f is the map g : Range f → R – { -4/3 } given by
Let f : R – { -4/3 } → R be a function defined as f(x) = ????????/3????+????. The inverse of f is the map g : Range f → R – { -4/3 } given by
CBSE | Class 12 | Exercise 1.3 | Maths | NCERT | Relations and Functions
Let f : R – { -4/3 } → R be a function defined as f(x) = ????????/3????+????. The inverse of f is the map g : Range f → R – { -4/3 } given by

(A) g(y) = 3y/(3-4y)                     (B) g(y) = 4y/(4-3y)

(C) g(y) = 4y/(3-4y)                     (D) g(y) = 3y/(4-3y)

solution:

Let f : R – { – 4/3 } → R be a capacity characterized as f(x) = 4????/

3????+4

. Also, Range f → R – { – 4/3 }

y = f(x) = 4????

3????+4

y(3x + 4) = 4x 3xy + 4y = 4x x(3y – 4) = – 4y

x = 4y/(4-3y)

In this manner, f-1 (y) = g(y) = 4y/(4-3y). Alternative (B) is the right reply.

i

More Material