Solution:
(i) Non-transitive:
If $p, q$ and $r \in A$ such that $(p, q) \in R$ and $(q, r) \in R \Rightarrow(p, r) \in R$, then $\mathrm{R}$ is transitive.
Here, $(1,2) \in \mathrm{R}$ and $(2,3) \in \mathrm{R}$ but $(1,3) \notin \mathrm{R}$
As a result, $R$ is not transitive.