Solution
False
As per the inquiry,
Allow us to expect to be that,
A = 25 cm
B = 5 cm
C = 24 cm
Presently, Using Pythagoras Theorem,
We have,
\[A2\text{ }=\text{ }B2\text{ }+\text{ }C2\]
\[B2\text{ }+\text{ }C2\text{ }=\text{ }\left( 5 \right)2\text{ }+\text{ }\left( 24 \right)2\]
\[B2\text{ }+\text{ }C2\text{ }=\text{ }25\text{ }+\text{ }576\]
\[B2\text{ }+\text{ }C2\text{ }=\text{ }601\]
\[A2\text{ }=\text{ }600\]
\[600\text{ }\ne \text{ }601\]
\[\begin{array}{*{35}{l}}
A2\text{ }\ne \text{ }B2\text{ }+\text{ }C2 \\
~ \\
\end{array}\]
Since the sides doesn’t fulfill the property of Pythagoras hypothesis, triangle with sides 25cm, 5cm and 24cm is certainly not a right triangle.