The given statement is false
Explanation:
Let us assume a be the side of square.
From the question we got that the circle is inscribed in the square.
Therefore, Diameter of circle = Side of square = a
Then Radius of the circle = \[a/2\]
Now we got Area of the circle = \[\pi {{r}^{2}}=\pi {{(a/2)}^{2}}=(\pi {{a}^{2}})/4\] \[c{{m}^{2}}\]
Therefore, area of the circle is \[(\pi {{a}^{2}})/4\] \[c{{m}^{2}}\]
Therefore the area of the circle inscribed in a square of side a cm is not \[{{a}^{2}}\] \[c{{m}^{2}}\]