Is the area of the circle inscribed in a square of side a cm, \[{{a}^{2}}\] \[c{{m}^{2}}\]? Give reasons for your answer.
Is the area of the circle inscribed in a square of side a cm, \[{{a}^{2}}\] \[c{{m}^{2}}\]? Give reasons for your answer.

The given statement is false

Explanation:

Let  us assume a be the side of square.

From the question we got  that the circle is inscribed in the square.

Therefore, Diameter of circle = Side of square = a

Then Radius of the circle = \[a/2\]

Now we got Area of the circle = \[\pi {{r}^{2}}=\pi {{(a/2)}^{2}}=(\pi {{a}^{2}})/4\] \[c{{m}^{2}}\]

Therefore, area of the circle is \[(\pi {{a}^{2}})/4\] \[c{{m}^{2}}\]

Therefore the area of the circle inscribed in a square of side a cm is not \[{{a}^{2}}\] \[c{{m}^{2}}\]