SOLUTION:
=
= …….(i)
Comparing coefficients of : A + +B + C = 0 …….(ii)
Comparing coefficients of : –B + 3C= 5 …….(iii)
Comparing constants: –4A – 2B + 2C = 0 …….(iv)
On solving eq. (i), (ii) and (iii), we get A = B = C =
Putting the values of A, B and C in eq. (i),
=
=
=53log|x+1|−52log|x+2|+56log|x−2|+c=53log|x+1|−52log|x+2|+56log|x−2|+c