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In the given triangle PQR, LM is parallel to QR and PM: MR = 3: 4. Calculate the value of ratio: Area of Δ LQM/ Area of Δ LQN

Selina Solutions Concise Class 10 Maths Chapter 15 ex. 15(C) - 6

Solution:

Because, \[\Delta \text{ }LQM\text{ }and\text{ }\Delta \text{ }LQN\] have common vertex at \[L\]and their bases \[QM\text{ }and\text{ }QN\] are along the same straight line.

\[Area\text{ }of\text{ }\Delta \text{ }LQM/\text{ }Area\text{ }of\text{ }\Delta \text{ }LQN\]

\[=\text{ }QM/QN\text{ }=\text{ }10/7\]

\[[Since,\text{ }MN/QN\text{ }=\text{ }3/7\Rightarrow QM/QN\text{ }=\text{ }10/7]\]