(i) A = {a, b, c, d}; B = {d, c, b, a}
The order in which a set’s elements are listed has no bearing.
Therefore, A = B.
(ii) A = {4, 8, 12, 16}; B = {8, 4, 16, 18}
We know that 12 ∈ A but 12 ∉ B.
Therefore, A ≠ B
(i) A = {a, b, c, d}; B = {d, c, b, a}
The order in which a set’s elements are listed has no bearing.
Therefore, A = B.
(ii) A = {4, 8, 12, 16}; B = {8, 4, 16, 18}
We know that 12 ∈ A but 12 ∉ B.
Therefore, A ≠ B