Solution:
According to the given question,
\[\angle AXY\text{ }=~\angle AYX\]
So, \[AX\text{ }=\text{ }AY\][Sides opposite to equal angles are equal.]
Also, from BPT we have
\[BX/AX\text{ }=\text{ }CY/AY\]
Thus,
\[AX\text{ }+\text{ }BX\text{ }=\text{ }AY\text{ }+\text{ }CY\]
So, \[AB\text{ }=\text{ }AC\]
Therefore, \[\vartriangle ABC\]is an isosceles triangle.