The possible outcomes when a die is thrown are $1,2,3,4,5$ and $6$.
Suppose that the die of red colour be $R$, die of white colour be $W$, and die of blue colour be $B$.
Then, the total number of sample space $ = {\text{ }}\left( {6{\text{ }} \times {\text{ }}3} \right)$
$ = {\text{ }}18$.
Therefore, the sample space of the event is
$\begin{array}{*{20}{l}}
{S = \{ \left( {R,1} \right),\left( {R,2} \right),\left( {R,3} \right),\left( {R,4} \right),\left( {R,5} \right),\left( {R,6} \right),} \\
{\;\;\;\;\;\;\left( {W,1} \right),\left( {W,2} \right),\left( {W,3} \right),\left( {W,4} \right),\left( {W,5} \right),\left( {W,6} \right),} \\
{\;\;\;\;\;\;\left( {B,1} \right),\left( {B,2} \right),\left( {B,3} \right),\left( {B,4} \right),\left( {B,5} \right),\left( {B,6} \right)\} }
\end{array}$