In shutting a pack of 52 playing cards, four are accidently dropped; find the chance that the missing cards should be one from each suit
In shutting a pack of 52 playing cards, four are accidently dropped; find the chance that the missing cards should be one from each suit

According to the question, a pack of 52 cards is given from which 4 are dropped.

By using the formula of probability, we have,

P (E) = favourable outcomes / total possible outcomes

Now find the probability that the missing cards should be one from each suit

We know from well shuffled pack of cards, 4 cards missed out total possible outcomes will be,

$n (S) = {}^{52}C_4 = 270725$

Let E be the event that four missing cards are from each suite

$n (E) = {}^{13}C_1\times {}^{13}C_1\times {}^{13}C_1\times {}^{13}C_1 = 134$

P (E) = n (E) / n (S)

= 134 / 270725

= 2197/20825