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In a single throw of three dice, find the probability of getting a total of 17 or 18
In a single throw of three dice, find the probability of getting a total of 17 or 18
CBSE | Class 11 | Exercise 33.3 | Maths | Probability | RD Sharma
In a single throw of three dice, find the probability of getting a total of 17 or 18

According to the question, three dice are thrown at once.

By using the formula of probability, we get,

P (E) = favourable outcomes / total possible outcomes

Total number of possible outcomes will be $6^3=216$

So, n (S) = 216

Let E be the event of getting total of 17 or 18

E = {(6, 6, 5) (6, 5, 6) (5, 6, 6) (6, 6, 6)}

n (E) = 4

P (E) = n (E) / n (S)

= 4 / 216

= 1/54

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