In a single throw of a die, find the probability that the number: \[\left( \mathbf{iii} \right)\]will be an odd number

Solution:

\[\left( iii \right)\] If \[E\text{ }=\]event of getting an odd number \[=\text{ }\left\{ 1,\text{ }3,\text{ }5 \right\}\]

So\[,\text{ }n\left( E \right)\text{ }=\text{ }3\]

Then, probability of a getting an odd number \[=\text{ }n\left( E \right)/\text{ }n\left( s \right)\text{ }=\text{ }3/6\text{ }=\text{ }{\scriptscriptstyle 1\!/\!{ }_2}\]