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In a single throw of a die, find the probability of getting a number: \[\left( \mathbf{iii} \right)\]not greater than \[\mathbf{4}\]
In a single throw of a die, find the probability of getting a number: \[\left( \mathbf{iii} \right)\]not greater than \[\mathbf{4}\]
CBSE | Class 10 | Selina | Statistics and Probability
In a single throw of a die, find the probability of getting a number: \[\left( \mathbf{iii} \right)\]not greater than \[\mathbf{4}\]

\[\left( iii \right)\text{ }E\text{ }=\] event of getting a number not greater than \[4\text{ }=\text{ }\left\{ 1,\text{ }2,\text{ }3,\text{ }4 \right\}\]

So\[,\text{ }n\text{ }\left( E \right)\text{ }=\text{ }4\]

Then, probability of getting a number not greater than \[4\text{ }=~n\left( E \right)/\text{ }n(s)\text{ }=~4/6\text{ }=\text{ }2/3\]

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