According to the question, a pair of dice has been thrown
So the number of elementary events in sample space will be $6^2=36$
n (S) = 36
By using the formula of probability, we get,
P (E) = favourable outcomes / total possible outcomes
(i) Let E be the event of getting total of 9 or 11
E = {(3,6) (4,5) (5,4) (5,6) (6,3) (6,5)}
n (E) = 6
P (E) = n (E) / n (S)
= 6 / 36
= 1/6
(ii) Let E be the event of getting total greater than 8
E = {(3,6) (4,5) (4,6) (5,4) (5,5) (5,6) (6,3) (6,4) (6,5) (6,6)}
n (E) = 10
P (E) = n (E) / n (S)
= 10 / 36
= 5/18