In a simultaneous throw of a pair of dice, find the probability of getting:
(i) an even number on one and a multiple of 3 on the other
(ii) neither 9 nor 11 as the sum of the numbers on the faces
In a simultaneous throw of a pair of dice, find the probability of getting:
(i) an even number on one and a multiple of 3 on the other
(ii) neither 9 nor 11 as the sum of the numbers on the faces

According to the question, a pair of dice has been thrown

So the number of elementary events in sample space will be $6^2=36$

n (S) = 36

By using the formula of probability, we get,

P (E) = favourable outcomes / total possible outcomes

(i) Let E be the event of getting even on one and multiple of three on other

E = {(2,3) (2,6) (4,3) (4,6) (6,3) (6,6) (3,2) (3,4) (3,6) (6,2) (6,4)}

n (E) = 11

P (E) = n (E) / n (S)

= 11 / 36

(ii) Let E be the event of getting neither 9 or 11 as the sum

E = {(3,6) (4,5) (5,4) (5,6) (6,3) (6,5)}

n (E) = 6

P (E) = n (E) / n (S)

= 6 / 36

= 1/6