Solution:
Let’s consider as the set of people in the committee who speak French as F, and
the set of people in the committee who speak Spanish as S.
$n\left( F \right)\text{ }=\text{ }50$
$n\left( S \right)\text{ }=\text{ }20$
$n(S~\cap ~F)\text{ }=\text{ }10$
This can be written as
$n(S~\cup ~F)\text{ }=~n\left( S \right)\text{ }+~n\left( F \right)-n(S~\cap ~F)$
Now, substitute the values
$n(S~\cup ~F)\text{ }=\text{ }20\text{ }+\text{ }50-10$
Calculating further
$n(S~\cup ~F)\text{ }=\text{ }70-10$
$n(S~\cup ~F)\text{ }=\text{ }60$
As a result, in the committee 60 people speak at least one of the two languages.