Solution:

As per the question,

60 = Total number of students

25 = Students who play cricket

20 = Students who play tennis

10 = Students who play both the games

We need to find: the number of students who play neither

Let S = the total number of students

Let C = the number of students who play cricket

Let T = the number of students who play tennis

$\mathrm{n}(\mathrm{S})=60, \mathrm{n}(\mathrm{C})=25, \mathrm{n}(\mathrm{T})=20, \mathrm{n}(\mathrm{C} \cap \mathrm{T})=10$

So, the no. of students who play either of them,

$n(C \cup T)=n(C)+n(T)-n(C \cap T)$

$=25+20-10$

$=35$

Therefore, No. of student who play neither = Total $-n(C \cup T)$ $=60-
35$ $=25$

As a result, number of students who play neither cricket nor tennis is 25.