Solution:
We have,
Total number of shirts \[=\text{ }50\]
Total number of elementary events \[=\text{ }50\text{ }=\text{ }n\left( S \right)\]
\[\left( i \right)\] As, trader accepts only good shirts and number of good shirts \[=\text{ }44\]
Event of accepting good shirts \[=\text{ }44\text{ }=\text{ }n\left( E \right)\]
Probability of accepting a good shirt \[=~n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }44/50\text{ }=\text{ }22/25\]
\[\left( ii \right)\] As, trader rejects shirts with major defects only and number of shirts with major defects \[=\text{ }2\]
Event of accepting shirts \[=\text{ }50\text{ }\text{ }2\text{ }=\text{ }48\text{ }=\text{ }n\left( E \right)\]
Probability of accepting shirts \[=~n\left( E \right)/\text{ }n\left( S \right)\text{ }=\text{ }48/50\text{ }=\text{ }24/25\]