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In ΔABC, ∠ABC = ∠DAC, AB = 8 cm, AC = 4 cm and AD = 5 cm. Find the area of ΔACD: area of ΔABC
In ΔABC, ∠ABC = ∠DAC, AB = 8 cm, AC = 4 cm and AD = 5 cm. Find the area of ΔACD: area of ΔABC
Class 10 | Exercise 15E | ICSE | Maths | Selina | Similarity (With Applications to Maps and Models)
In ΔABC, ∠ABC = ∠DAC, AB = 8 cm, AC = 4 cm and AD = 5 cm. Find the area of ΔACD: area of ΔABC

Selina Solutions Concise Class 10 Maths Chapter 15 ex. 15(E) - 12

Solution:

As, \[\vartriangle ACD\text{ }\sim\text{ }\vartriangle BCA\]

We have,

\[Ar\left( \vartriangle ACD \right)/\text{ }Ar\left( \vartriangle BCA \right)\]

\[=\text{ }A{{D}^{2}}/\text{ }A{{B}^{2}}~=\text{ }{{5}^{2}}/{{8}^{2}}\]

So,

\[Ar\left( \vartriangle ACD \right)/\text{ }Ar\left( \vartriangle BCA \right)\]

\[=\text{ }25/64\]

i

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