In Δ ABC, BM ⊥ AC and CN ⊥ AB; show that:
In Δ ABC, BM ⊥ AC and CN ⊥ AB; show that:

Selina Solutions Concise Class 10 Maths Chapter 15 ex. 15(A) - 6

Answer:

Selina Solutions Concise Class 10 Maths Chapter 15 ex. 15(A) - 7

In \[\Delta \text{ }ABM\text{ }and\text{ }\Delta \text{ }ACN,\]

\[\angle AMB\text{ }=\text{ }\angle ANC\] [Since, BM ⊥ AC and CN ⊥ AB]

\[\angle BAM\text{ }=\angle CAN\] [Common angle]

Thus, \[\vartriangle ABM\text{ }\sim\text{ }\vartriangle ACN\]by \[AA\]rule for similitude

In this way, by relating sides of comparative triangles we have

Selina Solutions Concise Class 10 Maths Chapter 15 ex. 15(A) - 8