$(x+a)$ is a factor of $2 x^{2}+2 a x+5 x+10$
$x+a=0$
$\Rightarrow \mathrm{x}=-\mathrm{a}$
Since, it satisfies the above polynomial.
=> $2(-a)^{2}+2 a(-a)+5(-a)+10=0$
$\Rightarrow 2 a^{2}-2 a^{2}-5 a+10=0$
$\Rightarrow-5 \mathrm{a}=-10$
$\Rightarrow \mathrm{a}=2$