If there’s the probability of winning a game is $0.3$, then find that what is the probability of losing it?

Given that probability of winning a game P(E) $=0.3$

We have To Find that Probability of losing the game

As We know that the sum of probability of occurrence of an event and probability of non-occurrence of an event is $1$.

Therefore,

$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=0.7$
$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=0.4$

$P(\overset{\scriptscriptstyle\rightharpoonup}{E})+P(E)=1$

$0.3+P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1$

$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1-0.3$

$P(\overset{\scriptscriptstyle\rightharpoonup}{E})=0.7$

Hence, the probability of losing the game is