Answer –
Magnetic field strength is given by B = 0.25 T
Magnetic moment is by M = 0.6 T-1
The angle θ between the direction of the applied field and the axis of the solenoid is 30°.
Therefore, the torque acting on the solenoid is given by the relation –
\[T=MB\sin \theta =0.6\times 0.25\times \sin {{30}^{\circ }}\]
\[T=7.5\times {{10}^{-2}}J\]