If the point $C(k, 4)$ divides the join of $A(2,6)$ and $B(5,1)$ in the ratio $2: 3$ then find the value of $\mathrm{k}$.
If the point $C(k, 4)$ divides the join of $A(2,6)$ and $B(5,1)$ in the ratio $2: 3$ then find the value of $\mathrm{k}$.

Since, the point $C(k, 4)$ divides the join of $A(2,6)$ and $B(5,1)$ in ratio $2: 3$. So

$
\begin{aligned}
&\mathrm{k}=\frac{2 \times 5+3 \times 2}{2+3} \\
&=\frac{10+6}{5} \\
&=\frac{16}{5} \\
&\text { Hence, } \mathrm{k}=\frac{16}{5}
\end{aligned}
$