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If $\sin x=\frac{12}{13}\,and\,\sin y=\frac{4}{5}$, where $\frac{\pi }{2}

Answer:

Given: $\sin x=\frac{12}{13}\,and\,\sin y=\frac{4}{5}$

Here we will find values of cosx and cosy

(i) sin(x + y) = sinx.cosy + cosx.siny

(ii)cos(x + y) = cosx.cosy + sinx.siny