If $\mathrm{P}(\mathrm{A})=3 / 5$ and $\mathrm{P}(\mathrm{B})=1 / 5$, find $\mathrm{P}(A \cap \mathrm{B})$ if $\mathrm{A}$ and $\mathrm{B}$ are independent events.

Solution:

Given: $P(A)=3 / 5$ and $P(B)=1 / 5$

As A and B are independent events.
So we know that for independent events,
$\Rightarrow P(A \cap B)=P(A) . P(B)$
Substituiting the values we get,

$=3 / 5 \times 1 / 5=3 / 25$
Thus the answer is 3/25.