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If \[\mathbf{P}\left( \mathbf{E} \right)\text{ }=\text{ }\mathbf{0}.\mathbf{59}\]; find \[\mathbf{P}\left( \mathbf{not}\text{ }\mathbf{E} \right)\]
If \[\mathbf{P}\left( \mathbf{E} \right)\text{ }=\text{ }\mathbf{0}.\mathbf{59}\]; find \[\mathbf{P}\left( \mathbf{not}\text{ }\mathbf{E} \right)\]
CBSE | Class 10 | Exercise 13.3 | Selina | Statistics and Probability
If \[\mathbf{P}\left( \mathbf{E} \right)\text{ }=\text{ }\mathbf{0}.\mathbf{59}\]; find \[\mathbf{P}\left( \mathbf{not}\text{ }\mathbf{E} \right)\]

Solution:

We know that,

\[P\left( E \right)\text{ }+\text{ }P\left( not\text{ }E \right)\text{ }=\text{ }1\]

So, \[0.59\text{ }+\text{ }P\left( not\text{ }E \right)\text{ }=\text{ }1\]

Hence, \[P\left( not\text{ }E \right)\text{ }=\text{ }1\text{ }\text{ }0.59\text{ }=\text{ }0.41\]

 

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