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If in two Δ PQR, AB/QR = BC/PR = CA/PQ, then (a)Δ PQR~Δ CAB (b) Δ PQR ~ Δ ABC (c)Δ CBA ~ Δ PQR (d) Δ BCA ~ Δ PQR
If in two Δ PQR, AB/QR = BC/PR = CA/PQ, then (a)Δ PQR~Δ CAB (b) Δ PQR ~ Δ ABC (c)Δ CBA ~ Δ PQR (d) Δ BCA ~ Δ PQR
CBSE | Class 10 | Exercise 6.1 | Maths | NCERT Exemplar | Triangles
If in two Δ PQR, AB/QR = BC/PR = CA/PQ, then (a)Δ PQR~Δ CAB (b) Δ PQR ~ Δ ABC (c)Δ CBA ~ Δ PQR (d) Δ BCA ~ Δ PQR

Solution:

(a)Δ PQR~Δ CAB

Explanation:

From triangles ABC and PQR, we have,

AB/QR = BC/PR = CA/PQ

When the sides of one triangle are proportional to the sides of the other given triangle, and even their corresponding angles are equal, both triangles are similar by SSS similarity criterion.

As a result, we have,

Δ CAB~Δ PQR

i

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