(a)Δ PQR~Δ CAB (b) Δ PQR ~ Δ ABC

(c)Δ CBA ~ Δ PQR (d) Δ BCA ~ Δ PQR

Solution:

(a)δ PQR~Δ CAB

Clarification:

From ∆ABC and ∆PQR, we have,

stomach muscle/QR = BC/PR = CA/PQ

In the event that sides of one triangle are relative to the side of the other triangle, and their comparing points are likewise equivalent, then, at that point both the triangles are comparative by SSS similitude.

Consequently, we have,

\[\Delta \text{ }PQR\tilde{\ }\Delta \text{ }CAB\]