If $f(x)=x^{4}-5 x+6$ is divided by $g(x)=2-x^{2}$.

$f(x)$ as $x^{4}+0 x^{3}+0 x^{2}-5 x+6$ and $g(x) a s-x^{2}+2$

Quotient $q(x)=-x^{2}-2$

Remainder $\mathrm{r}(\mathrm{x})=-5 \mathrm{x}+10$